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x^2-101x-500=0
a = 1; b = -101; c = -500;
Δ = b2-4ac
Δ = -1012-4·1·(-500)
Δ = 12201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12201}=\sqrt{49*249}=\sqrt{49}*\sqrt{249}=7\sqrt{249}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-101)-7\sqrt{249}}{2*1}=\frac{101-7\sqrt{249}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-101)+7\sqrt{249}}{2*1}=\frac{101+7\sqrt{249}}{2} $
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